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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+clc;
+r=4; // resistance of inductor
+v=8; // maximum voltage
+L=2; // inductance
+t=2; // time required to reach maximum voltage value
+disp('case a');
+// after solving laplace equation we get expression for i(t) (transient current) i.e i(t)=((exp^-2*t)+(2*t-1))/2
+// for t=2 sec i(t) is given by
+it=((exp(-2*t))+2*t-1)/2;
+E=(L*it^2)/2;
+printf('Energy stored during %d sec is %f J\n',t,E);
+disp('case b');
+i=v/r; // current when transients are over
+E=(L*i^2)/2;
+printf('Energy stored after transients are over is %d J\n',E);