initial commit / add all books

1 files changed, 32 insertions, 0 deletions

diff --git a/3760/CH1/EX1.49/Ex1_49.sce b/3760/CH1/EX1.49/Ex1_49.sce
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+clc;

+disp('case b');

+// KVA ratings and leakage impedances for the transformers are 

+k1=100; // KVA rating for transformer 1; 

+z1=0.02; // p u impedance for transformer 1; 

+k2=75; // KVA rating for transformer 2; 

+z2=0.03; // p u impedance for transformer 2; 

+k3=50; // KVA rating for transformer 3; 

+z3=0.025; // p u impedance for transformer 3;

+disp('case b(1)');

+// assumng k1 as a base KVA 

+S=225; // load which has to be shared by three transformers

+ze1=z1*100; // percentage impedance for transformer 1 

+ze2=(k1/k2)*z2*100; // percentage impedance for transformer 2

+ze3=(k1/k3)*z3*100; // percentage impedance for transformer 3

+zt=(1/ze1)+(1/ze2)+1/(ze3); // total percentage leakage impedance

+s1=S/(ze1*zt); 

+s2=S/(ze2*zt);

+s3=S/(ze3*zt);

+printf('load shared by transformer 1,2 and 3 are %f KVA, %f KVA and %f KVA respectively\n',s1,s2,s3);

+disp('case b(2)');

+// since transformer 1 has lowest leakage impedance among three, it will be loaded to its rated capacity

+S=k1*ze1*zt ; // total KVA shared

+printf('greatest load that can be shared by transformers is %f KVA\n',S);

+disp('case b(3)');

+// for successful parallel operation of transformer all the three leakage impedances based on their KVA rating  should be equal.Since magnitude of leakage impedance of transformer1 is fixed that is 2 percent z2=z3=2 percent

+ze1=2;

+ze2=ze1*(k1/k2);

+ze3=ze1*(k1/k3);

+zt=(1/ze1)+(1/ze2)+(1/ze3); // Total leakage impedance

+printf('magnitude of equivalent leakage impedance is %f percent\n',zt);

+