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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3760/CH1/EX1.27/Ex1_27.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3760/CH1/EX1.27/Ex1_27.sce')
-rw-r--r-- | 3760/CH1/EX1.27/Ex1_27.sce | 25 |
1 files changed, 25 insertions, 0 deletions
diff --git a/3760/CH1/EX1.27/Ex1_27.sce b/3760/CH1/EX1.27/Ex1_27.sce new file mode 100644 index 000000000..c9332db01 --- /dev/null +++ b/3760/CH1/EX1.27/Ex1_27.sce @@ -0,0 +1,25 @@ +clc;
+// subscripts 1 and 2 are used to indicate transformer of 11kv at 25hz and 22kv at 50 hz respectively
+// for same current power is doubled therefore P2=2P1
+poh1=1.8; // ohmic losses as a percentage of total power P1
+ph1=0.8; // hysteresis losses as a percentage of total power P1
+pe1=0.3; // eddy current losses as a percentage of total power P1
+poh2=poh1/2; // ohmic losses do not change with frequency but changes with voltage since p1=2p1 we get the result shown
+// since frequency also gets doubled whwn voltage levels double therefore there is no change in flux density i.e is Bm1=Bm2
+f1=25; // frequency in hertz
+f2=50; // frequency in hertz
+ph2=(f2/f1)*ph1; // hysteresis losses are directly proportional to frequency
+pe2=(f2/f1)^2*pe1; // eddy current losses are directly proportional to frequency
+// we know p2=2p1
+ph2p=ph2/2; // hysteresis losses as a percentage of total power P2
+pe2p=pe2/2; // eddy current losses as a percentage of total power P2
+printf('ohmic losses as a percentage of total power at 50 hz is %f percent\n',poh2);
+printf('hysteresis losses as a percentage of total power at 50 hz is %f percent\n',ph2p);
+printf('eddy current losses as a percentage of total power at 50 hz is %f percent\n',pe2p);
+// efficiency at f1,v1
+n1=(1-((poh1+ph1+pe1)/100)/(1+((poh1+ph1+pe1)/100)))*100;
+printf('efficiency at 25 hz is %f percent\n',n1);
+// efficiency at f2,v2
+n2=(1-((poh2+ph2p+pe2p)/100)/(1+((poh2+ph2p+pe2p)/100)))*100;
+printf('efficiency at 50 hz is %f percent',n2);
+
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