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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+clear//
+
+//Variables
+
+VCC = 10.0 //Source voltage (in volts)
+RE = 1.5 * 10**3 //Emitter resistance (in ohm)
+R1 = 30.0 * 10**3 //Resistance (in ohm)
+R2 = 20.0 * 10**3 //Resistance (in ohm)
+beta1 = 150.0 //Common emitter current gain
+beta2 = 100.0 //Common emitter current gain
+VBE = 0.7 //Emitter-to-base voltage (in volts)
+
+//Calculation
+
+Ai = beta1 * beta2 //Overall current gain of transistor
+VR2 = VCC * R2/(R1 + R2) //Voltage across resistor2 (in volts)
+VB2 = VR2 - VBE //Voltage at the base of Q2 (in volts)
+VE2 = VB2 - VBE //Voltage at the emitter of Q2 (in volts)
+IE2 = VE2 / RE //Emitter current of Q2 (in Ampere)
+r1e2 = 25.0/IE2 * 10**-3 //a.c. emitter diode resistance of Q2 (in ohm)
+IB2 = IE2 / beta2 //Base current of Q2 (in Ampere)
+IE1 = IB2 //Emitter current of Q2
+r1e1 = 25.0/IE1 * 10**-3 //a.c. emitter diode resistance of Q1 (in ohm)
+Ri1 = R1 * R2/(R1 + R2) //Total input resistance (in ohm)
+Av = RE/(r1e1/beta2 + r1e2 + RE) //Overall voltage gain
+
+//Result
+
+printf("\n The overall current gain is %0.3f .",Ai)
+printf("\n The a.c. emitter diode resistance of Q1 transistor is %0.1f ohm.\nThe a.c. emitter diode resistance of Q2 transistor is %0.2f ohm.",r1e1,r1e2)
+printf("\n Total input resistance is %0.3f kilo-ohm.",Ri1 * 10**-3)
+printf("\n Overall voltage gain is %0.2f .",Av)