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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3751/CH7/EX7.14/Ex7_14.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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diff --git a/3751/CH7/EX7.14/Ex7_14.sce b/3751/CH7/EX7.14/Ex7_14.sce new file mode 100644 index 000000000..9a4c66d2e --- /dev/null +++ b/3751/CH7/EX7.14/Ex7_14.sce @@ -0,0 +1,36 @@ +//Fluid Systems- By Shiv Kumar +//Chapter 7- Performance of Water Turbine +//Example 7.14 +//To Determine the Size (Scale Ratio) of the Model and To Find the Model Speed and Power. + + clc + clear + +//Given:- + TP=240000; //Total Power Produced, kW + n=4; //No. of Turbines + eta_o=91/100; //Effeciency of each turbine + Np=120; //Speed of each Turbine, rpm + Hp=70; //Head for each Turbine, m + + Qm=0.45; //Discharge for Model, m^3/s + Hm=5; //Head for testing the Model, m + +//Data Required:- + rho=1000; //Density of Water, Kg/m^3 + g=9.81; //Acceleratrion due to gravity, m/s^2 + +//Calculations:- + Pp=TP/n; //Power produced from each Turbine, kW + Qp=Pp*1000/(rho*g*Hp*eta_o); //Discharge passing through one Turbine, m^3/s + DmbyDp=(Qm/Qp)^(1/2)*(Hp/Hm)^(1/4); //From Relation of Flow Coefficient + Lr=DmbyDp; //Scale Ratio + Nm=(Np/DmbyDp)*(Hm/Hp)^(1/2); //rpm + Pm=Pp*(Nm/Np)^3*DmbyDp^5; //KW + +//Results + printf("The Scale Ratio is 1:%.2f\n ",1/Lr) + printf("Model Speed, Nm=%.2f rpm\n",Nm) + printf("Model Power, Pm=%.2f kW\n",Pm) //The Answer vary due to Round off Error + + |