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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Fluid system - By - Shiv Kumar
+//Chapter 4 - Pelton Turbine (Impulse Turbine)
+//Example 4.8
+ clc
+ clear
+
+//Given Data:-
+ Cv=0.97; //Co-efficient of Velocity
+ H_l=400; //Head at lake, m
+ d=80; //Diameter of Jet, mm
+ D_pipe=0.6; //Diameter of pipe, m
+ l=4; //Length of pipe, m
+ f_dash=0.032; //Friction factor
+ AoD=165; //Angle of Deflection, degrees
+ beta_o=180-AoD; //degrees
+ // As bucket runs at 0.48 Jet speed
+ u_by_Vi=0.48; //u/Vi
+ Vel_per=15; //percentage by which velocity is reduced
+ eta_m=90/100; //Mechanical Efficiency
+
+//Data Used:-
+ rho=1000; //Density of water, kg/m^3
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+//Computations:-
+ d=d/1000; //m
+ l=l*1000; //m
+ Vro_by_Vri=1-Vel_per/100; //Vro/Vri
+ //using continuity equation,
+ V_by_Vi=(d/D_pipe)^2; //V/Vi
+ Vi=sqrt((2*g*H_l)/(1/Cv^2+f_dash*l*V_by_Vi^2/D_pipe)); //m/s
+ Vwi=Vi;
+ u=Vi*u_by_Vi; //m/s
+ ui=u;
+ uo=u;
+ Vri=Vi-ui; //m/s
+ Vro=Vri*Vro_by_Vri; //m/s
+ Vrwo=Vro*cosd(beta_o); //m/s
+ //(i) Flow Rate, Q
+ Q=(%pi/4)*d^2*Vi; //m^3/s
+ //(ii) Shaft Power, P
+ Vwo=uo-Vrwo; //m/s
+ Pr=rho*Q*(Vwi-Vwo)*u/1000; //Power developed by the runner, kW
+ P=eta_m*Pr; //kW
+
+//Results:-
+ printf("Flow Rate, Q=%.4f m^3/s \n", Q) //The answer vary due to round off error
+ printf("Shaft power, P=%.2f kW", P) //The answer vary due to round off error
+