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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3751/CH16/EX16.18 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3751/CH16/EX16.18')
| -rw-r--r-- | 3751/CH16/EX16.18/Ex16_18.sce | 28 |
1 files changed, 28 insertions, 0 deletions
diff --git a/3751/CH16/EX16.18/Ex16_18.sce b/3751/CH16/EX16.18/Ex16_18.sce new file mode 100644 index 000000000..c2a88b031 --- /dev/null +++ b/3751/CH16/EX16.18/Ex16_18.sce @@ -0,0 +1,28 @@ +//Fluid Systyems - By Shiv Kumar +//Chapter 16- Hydraulic Power and Its Transmission +//Example 16.18 +//To Find (i)The Load Lifted by Crane (ii)The Quantity of Water needed to Lift the Load. + + clc + clear + +//Given Data:- + d=200; //Diameter of Ram, mm + p=7.5; //Pressure of Water Supplied, MPa + VR=6; //Velocity Ratio + eta=50/100; //Efficiency of Crane + h=10; //Height through which water is to be lifted, m] + +//Computations:- + d=d/1000; //m + p=p*10^6; //Pa + + Fp=(%pi/4)*d^2*p; //Pressure Force Exerted on Ram, N (answer vary due to value of %pi) + W=Fp*eta/VR; //Load Lifted by Crane, N + Vw=(%pi/4)*d^2*h/VR*1000; //Quantity of Water needed, Litres + +//Results:- + printf(" (i)The Load Lifted by Crane, W=%.f N \n",W) //The answer provided in textbook is wrong + printf(" (ii)The Quantity of Water needed to Lift the Load by 10 m =%.2f Litres \n",Vw) //The answer vary due to round off error + + |