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+//Fluid Systems - By - Shiv Kumar
+//Chapter 12- Reciprocating Pumps
+//Example 12.12
+//To Find the  Maximum Speed at which the Pump may run without seperation.
+
+        clc
+         clear
+  
+//Given Data:-
+        D=10;       //Plunger Diameter, cm
+        L=20;        //Stroke Length, cm
+        H_s=4;      //Suction Head, m
+        H_d=14;     //Delivery Head, m
+        d_s=4;       //Diameter of Suction Pipe, cm
+        l_s=6;        //Length of Suction Pipe, m
+        d_d=3;       //Diameter of Delivery Pipe, cm
+        l_d=18;        //Length of Delivery Pipe, m
+        p=7.85;      //Pressure (below atm.) for seperation, N/cm^2
+        H_a=10.3;         //Atmospheric Pressure Head, m of water 
+
+
+//Data Used:-
+      g=9.81;       //Acceleration due to gravity, m/s^2
+      rho=1000;    //Density of water, kg/m^3
+
+
+//Computations:-
+         d_s=d_s/100;    //m
+         d_d=d_d/100;     //m
+         D=D/100;       //m
+         L=L/100;      //m
+
+         a_s=(%pi/4)*d_s^2;      //m^2
+         a_d=(%pi/4)*d_d^2;      //m^2
+         A=(%pi/4)*D^2;      //m^2
+         r=L/2;       //m
+
+        H_sp=p*100^2/(rho*g);     //Pressure Head of water for seperation, m (below atmosphere)    (Value given in textbook is wrong due to incorrect value of p is used)
+        H_abs=H_a-H_sp;      //Absolute Pressure Head of water for seperation, m 
+        H_as_by_omega2=(l_s/g)*(A/a_s)*r;       //H_as/omega^2
+        omega=sqrt((H_sp-H_s)/H_as_by_omega2);    //rad/s
+        N_s=omega*60/(2*%pi);     //rpm
+
+        H_ad_by_omega2=(l_d/g)*(A/a_d)*r;       //H_as/omega^2
+        omega=sqrt((H_sp+H_d)/H_ad_by_omega2);    //rad/s
+        N_d=omega*60/(2*%pi);     //rpm
+
+    //Selecting maximum speed,    
+     if N_s>N_d then 
+       N=N_s;
+      else
+        N=N_d;
+
+//Result:-
+   printf("Hence, The Maximum Speed at which Pump should be Run is %.2f rpm\n",N)       //The answer vary due to round off error
+
+