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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// Ex 62 Page 403
+
+clc;clear;close;
+// Given
+R=150;//ohm
+Vrms=200;//V
+Rd1=65;//ohm
+Rd2=140;//ohm
+
+Vm=Vrms/sqrt(2);//V
+//v=Vm*sin(theta)
+Rf=R+Rd1;//ohm
+Rb=R+Rd2;//ohm
+//i_f=v/Rf;//A
+//i_b=v/Rb;//A
+Irms=1/2/%pi*(integrate('(sqrt(2)*sin(theta))**2','theta',0,%pi)+integrate('(sqrt(2)/3*sin(theta))**2','theta',%pi,2*%pi))
+Iav=1/2/%pi*(integrate('sqrt(2)*sin(theta)','theta',0,%pi)+integrate('sqrt(2)/3*sin(theta)','theta',%pi,2*%pi))
+printf("reading of ammeter 1= %.2f A",Irms)
+printf("\n reading of ammeter 2 = %.2f A",Iav)
+P=1/2*(Vrms**2/Rf+Vrms**2/Rb);//W
+printf("\n\n Power taken from the mains = %.1f W",P)
+Pc=Irms**2*R;//W
+Pd=P-Pc;//W
+printf("\n Power dissipated in rectifying device = %d W",Pd)
+//Answer wrong in the textbook.