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+// Ex 3 Page 341
+
+clc;clear;close;
+// Given
+N=680; // turns
+fi=1.6*10^3 ;// Wb
+d1=4/100 ;// m
+d2=24/100;//m
+l=0.6;//m
+mu0=4*%pi/10^7 ;// constant
+
+
+// For air gap : 
+A=d1^2 ;// m^2
+Bg=fi/A ;//weber/m^2
+Hg=Bg/mu0;//AT/m
+mmf1=0.001/mu0 ;// AT
+
+// For central limb : 
+A=d1^2;// m^2
+Bc=fi/A ;//weber/m^2
+Hc=900;//AT/m (from magnetization curve)
+mmf2=Hc*d2 ;// AT
+
+
+// For side limb : 
+fi=1/2*fi ;// Wb
+A=d1^2;// m^2
+Bc=fi/A ;//weber/m^2
+Hc=520;//AT/m (from magnetization curve)
+mmf3=Hc*l ;// AT
+
+mmf_total = mmf1+mmf2+mmf3;// AT
+i=mmf_total/N ;// A
+printf("Current required  = %0.2f A",i)
+
+
+// Answer in the textbook are not accurate