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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 32_5
+clc;funcprot(0);
+//Given data
+L_1=60;// Load in MW
+L_2=60;// Load in MW
+L_3=30;// Load in MW
+T_12=8000;// Running time in hours
+T_3=2000;// Running time in hours
+E=876*10^6;// kWh per year
+
+//Calculation
+P=L_1+L_2+L_3;// Plant capacity in MW
+L_a=(E/8760)/1000;// MW
+F_l=(L_a/P)*100;// Load factor in %
+L=60;// L_1=L_2=L in MW
+ME=(2*L*T_12)+(1*L_3*T_3);// Maximum possile energy which can be produced by the plant in MEWh
+Puf=(E/(ME*10^3));// Plant use factor
+printf('\nLoad factor=%0.0f percentage \nPlant use factor=%0.2f',F_l,Puf);