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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 32_24
+clc;funcprot(0);
+//Given data
+P=60;// MW
+n_o=25/100;// The over all efficiency
+CV=30000;// The calorific value of value in kJ/kg
+F_l=30/100;// Load factor
+
+// Calculation
+I=(1/n_o)*3600;// Input in kJ
+Cc=(I/CV);// Consumption of coal per kW-hr in kg
+E=F_l*P*10^3*24;// kW-hr
+Cc_d=(E*Cc)/1000;// Consumption of coal per day in tons
+printf('\nConsumption of coal per kW-hr=%0.2f kg \nConsumption of coal per day=%0.1f tons',Cc,Cc_d);