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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 32_19
+clc;funcprot(0);
+//Given data
+L_max=5;// MW
+P=7;// Plant capacity in MW
+
+// Calculation
+//(a)
+t=[0 12 6];// Time in hours
+x=[6 12 6];
+a=[6 6 6];
+b=[5 5 5];// MW
+for(i=1:3)
+L=(b(i)/a(i))*sqrt((2*a(i)*x(i))-((x(i))^2));
+end
+b=5;// MW
+L_av=(%pi*b)/4;// Average load in MW
+// (i)
+F_l=L_av/L_max;// Load factor
+E=L_av*12;// Energy used during 12-hrs period MW hr
+CF=L_av/P;// Capacity factor
+printf('\n(a)The average load of the factory=%0.3f MW \n Load factor of the factory=%0.3f MW \n Energy consumed by the factory during 12 hours=%0.1f MW-hr \n Capacity factor=%0.3f',L_av,F_l,E,CF);
+//(b)
+b=5;
+a=4;
+t=[0 8 4];// Time in hours
+for(i=1:3)
+ L(i)=2+((b/a)*sqrt((2*a*t(i))-(t(i))^2));
+end
+L_av=(L(1)+L(2)+L(3))/3;// Average load in MW
+printf('\n(b)The average load of the factory=%0.2f MW',L_av);
+// The answer vary due to round off error