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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 32_10
+clc;funcprot(0);
+//Given data
+ML=30;// Maximum load in MW
+ml=10;// Minimum load in MW
+L_p=72;// Peak load in MWh/day
+
+// Calculation
+// From Fig.Prob.32.10
+// Area BGFA=(1/2)*xy-72;
+// FED=(1/2)*(20-x)*(24-y);
+function[X]=capacity(y)
+ X(1)=(y(1)*y(2)-144)-(0.45*(20-y(1))*(24-y(2)));
+ X(2)=(y(1)/y(2))-(20/24);
+endfunction
+y=[1 1];
+z=fsolve(y,capacity);
+x=z(1);// Hydel capacity in MW
+Spc=ML-x;// Steam plant capacity in MW
+printf('\nHydel plant capacity=%0.0f MW \nSteam plant capacity=%0.0f MW',x,Spc);
+// The answer provided in the textbook is wrong