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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3733/CH2/EX2.8 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3733/CH2/EX2.8')
| -rw-r--r-- | 3733/CH2/EX2.8/Ex2_8.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/3733/CH2/EX2.8/Ex2_8.sce b/3733/CH2/EX2.8/Ex2_8.sce new file mode 100644 index 000000000..f6bf15b38 --- /dev/null +++ b/3733/CH2/EX2.8/Ex2_8.sce @@ -0,0 +1,21 @@ +// Example 2_8
+clc;funcprot(0);
+//Given data
+A=50;// Area in sq.km
+H_1=100;// Head in m
+E=13.5*10^6;// The energy utilised by the customer in kWh
+n_g=0.75;// The over all generation efficiency
+rho_w=1000;// kg/m^3
+g=9.81;// m/s^2
+
+//Calculation
+// V=A*H;// Water used during 5 hours in m^3
+// Q=(A*H)/(5*3600);(discharge/sec)
+function[X]=head(y)
+ X(1)=E-(5*(rho_w*((A*10^6*y(1))/(5*3600))*g*(H_1/1000)*n_g));
+endfunction
+y=[10];
+z=fsolve(y,head);
+H=z(1);// metres
+printf('\nThe fall in the height of water in the reservoir=%0.2f metres',H);
+// The answer provided in the textbook is wrong
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