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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3733/CH18/EX18.2/Ex18_2.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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diff --git a/3733/CH18/EX18.2/Ex18_2.sce b/3733/CH18/EX18.2/Ex18_2.sce new file mode 100644 index 000000000..05b986b66 --- /dev/null +++ b/3733/CH18/EX18.2/Ex18_2.sce @@ -0,0 +1,35 @@ +// Example 18_2
+clc;funcprot(0);
+//Given data
+m_w1=400;// Quantity of cooling water in kg/min
+T_1=43.5;// The temperature of water at inlet in °C
+T_a1=18.5;// °C
+RH=60;// Relative humidity in %
+T_a2=27;// °C
+V=600;// Volume of air per minute in m^3/min
+P=4;// Power absorbed in kW
+C_pw=4.2;// kJ/kg°C
+
+//Calculation
+//The conditions of air at inlet and outlet are represented on psychrometric chart as shown in Fig.Prob.18.2
+// Total heat of air at inlet + Total heat of water at inlet + heat dissipatedby motor = Total heat of air at outlet + Total heat of water at outlet
+// From psychrometric chart,
+H_a1=38.87;// kJ/kg
+H_a2=84.85;// kJ/kg
+w_1=7.8;// grams/kg
+w_2=22.6;// grams/kg
+v_s1=0.836;// m^3/kg
+m_a=V/v_s1;// kg/min
+Q=P*60;// kJ/min
+//T_2=y(1)
+function[X]=Temperature(y);
+ X(1)=((m_w1*C_pw*(T_1-y(1)))+Q)-(m_a*((H_a2-H_a1)-(((w_2-w_1)/1000)*C_pw*y(1))));
+endfunction
+y=[10]
+z=fsolve(y,Temperature);
+T_2=z(1);// The temperature of water coming out of the tower in °C
+m_m=m_a*((w_2-w_1)/1000);// The make up water required per hour in kg/min
+printf('\nThe temperature of water coming out of the tower=%0.2f°C \nThe make up water required per hour=%0.1f kg/min',T_2,m_m);
+// The answers provided in the textbook is wrong
+
+
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