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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Chapter 4: Selection of Motor Power Rating
+//Example 2
+clc;
+
+//Variable Initialization
+N=200 //Speed in rpm
+Tc=25000 //Constant Torque in N-m
+J=10000 //Moment of inertia in Kg-m2
+
+//Given Duty Cycles
+t1=10 //For full speed and at constant torque
+t2=1 //For no load at full speed
+t3=5 //For speed reversal from N to -N
+t4=1 //For no load at full speed
+T5=20000 //Torque in N-m
+t5=15 //At full speed and at a torque T1
+t6=1 //For no operation at full speed
+t7=5 //For speed reversal from -N to N
+t8=1 //For no load operation
+
+
+//Solution
+
+Tr=J*(N-(-N))*2*%pi/60/5 //Reversal torque
+x=Tc**2*t1+Tr**2*t3+T5**2*t5+Tr**2*t7
+t=t1+t2+t3+t4+t5+t6+t7+t8 //Total Time
+Trms=sqrt(x/t) //rms torque
+
+Trated=Trms //Rated torque is equal to the rms torque
+Pr=Trated*2*%pi*200/60 //Power rating
+r=Tr/Trms //Ratio of reversal torque to the rms torque
+Pr=Pr*1e-3
+
+mprintf("Torque of motor is :%d N-m",Trms)
+
+if r < 2 then
+disp("Trms is rated equal to the Motor")
+mprintf(" Trms=%d N-m\n",Trms)
+end
+
+mprintf(" Power rating :%.3f kW",Pr)
+//The answer provided in the textbook is wrong