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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3731/CH2/EX2.3/Ex2_3.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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diff --git a/3731/CH2/EX2.3/Ex2_3.sce b/3731/CH2/EX2.3/Ex2_3.sce new file mode 100644 index 000000000..8940ec2c5 --- /dev/null +++ b/3731/CH2/EX2.3/Ex2_3.sce @@ -0,0 +1,28 @@ +//Chapter 2:Dynamics of Electric Drives
+//Example 3
+clc;
+
+//Variable Initialization
+Tlh=1000 // load torque in N-m
+Tmax=700 // maximum motor torque
+Tll=200 // light load for the motor to regain its steady state
+Tmin=Tll // minimum torque
+t_h=10 // period for which a load torque of 1000 N-m is apllied in sec
+Jm=10 // moment of inertia of the motor in Kg-m2
+No=500 // no load speed in rpm
+Tr=500 // torque at a given no load speed in N-m
+
+//Solution
+Wmo=No*2*%pi/60 // angular no load speed in rad/sec
+s=0.05 // slip at a torque of 500 N-m
+Wmr=(1-s)*Wmo // angular speed at a torque of 500 N-m in rad/sec
+
+y=log((Tlh-Tmin)/(Tlh-Tmax))
+x=Tr/(Wmo-Wmr)
+
+J=x*t_h/y
+Jf=J-Jm
+
+//Result
+//Answer Provided in the textbook is wrong
+mprintf("\n\nMoment of inertia of the flywheel : %.1f Kg-m2",Jf)
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