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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Chapter 3: Thermodynamic and Chemical Equilibrium
+//Problem: 21
+clc;
+
+//Declaration of Variables
+Kc = 0.5 // mole square litre square
+T = 400 // K
+R = 0.082 // litre atm per degree per mole
+
+// Solution
+Kp = Kc * (R * T) ** (-2)
+
+mprintf("The given equilibrium is\n")
+mprintf(" N2(g) + 3H2(g) <--> 2NH3(g)\n")
+mprintf(" Kp is %.3e",Kp)