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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3718/CH3/EX3.21/Ex3_21.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3718/CH3/EX3.21/Ex3_21.sce')
-rw-r--r-- | 3718/CH3/EX3.21/Ex3_21.sce | 15 |
1 files changed, 15 insertions, 0 deletions
diff --git a/3718/CH3/EX3.21/Ex3_21.sce b/3718/CH3/EX3.21/Ex3_21.sce new file mode 100644 index 000000000..35b67c388 --- /dev/null +++ b/3718/CH3/EX3.21/Ex3_21.sce @@ -0,0 +1,15 @@ +//Chapter 3: Thermodynamic and Chemical Equilibrium
+//Problem: 21
+clc;
+
+//Declaration of Variables
+Kc = 0.5 // mole square litre square
+T = 400 // K
+R = 0.082 // litre atm per degree per mole
+
+// Solution
+Kp = Kc * (R * T) ** (-2)
+
+mprintf("The given equilibrium is\n")
+mprintf(" N2(g) + 3H2(g) <--> 2NH3(g)\n")
+mprintf(" Kp is %.3e",Kp)
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