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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Ex20_1 Page:390 (2014)
+clc;clear;
+e = 1.6e-019; // Energy equivalent of 1 eV, J/eV
+m = 1.67e-027; // Mass of a nucleon, kg
+h = 6.626e-034; // Planck's constant, Js
+E = 30; // Energy of alpha particle, MeV
+r = 1.2e-015; // Nuclear constant, m
+lambda_p = h/sqrt(2*m*E*1e+006*e); // de-Broglie wavelength of the proton, m
+lambda_a = h/sqrt(2*4*m*E*1e+006*e); // de-Broglie wavelength of the alpha particle, m
+d = 2*r; // size of the nucleon, m
+printf("\nThe wavelength of the proton = %3.1e m", lambda_p);
+printf("\nThe wavelength of the alpha particle = %3.1e m", lambda_a);
+if ((lambda_p - d) < (lambda_a - d)) then
+ printf("\nThe proton is better for studying the nuclear details.")
+else
+ printf("\nThe alpha particle is better for studying the nuclear details.")
+end
+
+// Result
+// The wavelength of the proton = 5.2e-015 m
+// The wavelength of the alpha particle = 2.6e-015 m
+// The alpha particle is better for studying the nuclear details. \ No newline at end of file