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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+////Given
+a=10.0**-14 //m
+m=1.6*10**-27 //mass of a nucleon in kg
+h=1.054*10**-34 //Js
+
+//Calculation
+//
+Emin=((3*(%pi**2)*(h**2))/(2.0*m*(a**2)))/(1.6*10**-19)
+
+//Result
+printf("\n minimum energy of a nucleon is %0.1f Mev",Emin*10**-6)