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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+////Given
+lembda=3500*10**-10 //m
+h=6.6*10**-34
+c=3*10**8 //m/s
+
+//calculation
+E=((h*c)/lembda)/1.6*10**-19
+
+//Result
+printf("\n Energy is %0.2f ev",E*10**38)
+printf("\n 1.9 ev < E < 4.2 ev,only metal B will yield photoelectrons")