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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+b=200//width, in mm
+D=480//overall depth, in mm
+Ast=4*0.785*25^2//four 25 mm dia bars on tension side, in sq mm
+Asc=3*0.785*22^2//three 22 mm dia bars on compression side, in sq mm
+bottom_cover=30//in mm
+top_cover=30//in mm
+d=D-bottom_cover//effective depth, in mm
+m=18.66//modular ratio
+M=100*10^6//in N-mm
+//to find x using b(x^2)/2 + (1.5m-1)Asc(x-d')=mAst(d-x), which becomes of the form px^2+qx+r=0
+p=b/2
+q=(1.5*m-1)*Asc+m*Ast
+r=-(1.5*m-1)*Asc*top_cover-m*Ast*d
+x=(-q+sqrt(q^2-4*p*r))/(2*p)//in mm
+//sigma_cbc_dash=sigma_cbc*(x-d')/x=a*sigma_cbc
+a=(x-top_cover)/x
+sigma_cbc=M/(b*x*(d-x/3)/2+(1.5*m-1)*Asc*a*(d-top_cover))//in MPa
+sigma_st=m*sigma_cbc*(d-x)/x//in MPa
+sigma_cbc_dash=a*sigma_cbc//in MPa
+sigma_sc=1.5*m*sigma_cbc_dash//in MPa
+mprintf("Stress in concrete=%f N/mm^2\nStress in tension steel=%f N/mm^2\nStress in compression steel=%f N/mm^2",sigma_cbc,sigma_st,sigma_sc)