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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+Pu=2000//in kN
+Mux=50//in kN-m
+Muy=Mux
+fck=20//in MPa
+fy=415//in MPa
+//assume 2% steel
+p=2//in %
+Ag=Pu*10^3/(0.4*fck*(1-p/100)+0.67*fy*p/100)//in sq mm
+L=sqrt(Ag)//assuming a square column
+L=400//in mm
+m=Pu*10^3/fck/L/L
+n=p/fck
+c=50//cover (assume), in mm
+d1=c/L//d1=d'/D
+//from Fig. 19.21, for d'/D = 0.15 and Pu / fck b D = 0.625
+f=0.046
+Mux1=f*fck*L*L^2/10^6//in kN-m
+Muy1=Mux1
+Puz=(0.45*fck*(1-p/100)*L^2+0.75*fy*p/100*L^2)/10^3//in kN
+a=Pu/Puz//>0.8
+an=2
+b=(Mux/Mux1)^an+(Muy/Muy1)^an//>1
+//assume 2.5% steel
+p=2.5//in %
+n=p/fck
+//from Fig. 19.21, for d'/D = 0.15 and Pu / fck b D = 0.625
+f=0.08
+Mux1=f*fck*L*L^2/10^6//in kN-m
+Muy1=Mux1
+Puz=(0.45*fck*(1-p/100)*L^2+0.75*fy*p/100*L^2)/10^3//in kN
+a=Pu/Puz//<0.8
+an=1+1/0.6*(a-0.2)
+b=(Mux/Mux1)^an+(Muy/Muy1)^an//<1, hence OK
+Asc=p/100*L^2//in sq mm
+//provide 12-22 mm dia bars
+Asc=12*0.785*22^2//in sq mm
+mprintf("Summary of design:\nColumn size - %d x %d mm\nSteel-main = 12-22 mm dia bars placed equally on four faces of the column",L,L)