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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3682/CH2/EX2.3 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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Diffstat (limited to '3682/CH2/EX2.3')
| -rw-r--r-- | 3682/CH2/EX2.3/Ex2_3.sce | 19 |
1 files changed, 19 insertions, 0 deletions
diff --git a/3682/CH2/EX2.3/Ex2_3.sce b/3682/CH2/EX2.3/Ex2_3.sce new file mode 100644 index 000000000..317bbd0ab --- /dev/null +++ b/3682/CH2/EX2.3/Ex2_3.sce @@ -0,0 +1,19 @@ +// Exa 2.3
+
+clc;
+clear;
+
+// Given data
+
+// Single op-amp amplifier.
+ACL = 5; // Required gain(positive)
+
+// Solution
+
+disp("Since the gain is positive, we have to make a non-inverting amplifier.");
+disp("Referring Fig. 2.7(a), select R1 = 10 kΩ.");
+R1 = 10*10^3; //Input resistance in Ω
+// Then from eqn. (2.20), we get, ACL = 1+ (Rf/R1);
+// Therefore
+Rf = (ACL-1)*R1; //Feedback resistance in Ω
+printf(' The calculated feedback resistance of amplifier i.e Rf = %d kΩ.\n',Rf/1000);
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