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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3682/CH2/EX2.10/Ex2_10.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3682/CH2/EX2.10/Ex2_10.sce')
| -rw-r--r-- | 3682/CH2/EX2.10/Ex2_10.sce | 26 |
1 files changed, 26 insertions, 0 deletions
diff --git a/3682/CH2/EX2.10/Ex2_10.sce b/3682/CH2/EX2.10/Ex2_10.sce new file mode 100644 index 000000000..f7d84bca8 --- /dev/null +++ b/3682/CH2/EX2.10/Ex2_10.sce @@ -0,0 +1,26 @@ +// Exa 2.10
+
+clc;
+clear;
+
+// Given data
+
+// A current mirrir as shown in Fig. 2.16
+Ic = 1; // mA
+Vcc = 10; // Volts
+B = 125;
+Vbe = 0.7; // Bolts
+
+// Solution
+
+// Case(1)- When Ic = 1mA.
+printf(' From equations 2.67 and 2.68 we get R1 as - \n\n');
+// Ic = (B/(B+2))*((Vcc-Vbe)/R1);
+// Therefore
+R1 = (B/(B+2))*((Vcc-Vbe)/Ic);
+printf(' The value of R1 when Ic = 1 mA is R1 = %.2f kΩ. \n',R1);
+
+// Now case(2)- when Ic = 10 μA.
+Ic1 = 10*10^-3; // in mA
+R2 = (B/(B+2))*((Vcc-Vbe)/Ic1);
+printf(' The value of R1 when Ic = 10 μA is R1 = %d kΩ. \n',R2);
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