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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Estimating the temperature of the hot spot
+clc;
+disp('Example 4.6, Page No. = 4.11')
+// Given Data
+t = 0.5;// Plate width of transformer core in meter
+Ki = 0.94;// Stacking Factor
+p_core = 3;// Core loss in Watt per kg
+thermal_conductivity = 150;// Thermal conductivity in Watt per degree celsius
+Ts = 40;// Surface temperature in degree celsius
+D = 7800;// Density of steel plate in kg per meter cube
+// Calculation of the temperature of the hot spot
+q = p_core*Ki*D;// Core loss per unit volume (Watt per meter cube)
+p = 1/thermal_conductivity;// thermal resistivity
+x =t;// Since heat is taken all to one end
+Tm = (q*p*x*x/2)+Ts;// Temperature of the hot spot, if heat is taken all to one end (degree celsius)
+disp(Tm,'(a) Temperature of the hot spot, if heat is taken all to one end (degree celsius)=');
+//in book answers is 58.3 degree celsius. The answers vary due to round off error
+x =t/2;// Since heat is taken to both the directions
+Tm = (q*p*x*x/2)+Ts;// Temperature of the hot spot, if heat is taken to both the directions (degree celsius)
+disp(Tm,'(b) Temperature of the hot spot, if heat is taken to both the directions (degree celsius)=');
+//in book answers is 44.6 degree celsius. The answers vary due to round off error