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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 9_19 page no:377
+clc;
+Z1real=4;
+Z1img=8;
+Z1mag=sqrt(Z1real^2+Z1img^2);
+Z1ang=atand(Z1img/Z1real);
+Z2real=3;
+Z2img=4;
+Z2mag=sqrt(Z2real^2+Z2img^2);
+Z2ang=atand(Z2img/Z2real);
+Z3real=15;
+Z3img=20;
+Z3mag=sqrt(Z3real^2+Z3img^2);
+Z3ang=atand(Z3img/Z3real);
+Vl=400;
+Vrnmag=230.94;
+Vrnang=0;
+Vynmag=230.94;
+Vynang=-120;
+Vbnmag=230.94;
+Vbnang=-240;
+//calculating the line currents
+Irmag=Vrnmag/Z1mag;
+Irang=Vrnang-Z1ang;
+Irreal=Irmag*cosd(Irang);
+Irimg=Irmag*sind(Irang);
+Iymag=Vynmag/Z2mag;
+Iyang=Vynang-Z2ang;
+Iyreal=Iymag*cosd(Iyang);
+Iyimg=Iymag*sind(Iyang);
+Ibmag=Vbnmag/Z3mag;
+Ibang=Vbnang-Z3ang;
+Ibreal=Ibmag*cosd(Ibang);
+Ibimg=Ibmag*sind(Ibang);
+disp(Irmag,"the magnitude of Ir current is (in A)");
+disp(Irang,"the angle of Ir current is (in degree)");
+disp(Iymag,"the magnitude of Iy current is (in A)");
+disp(Iyang,"the angle of Iy current is (in degree)");
+disp(Ibmag,"the magnitude of Ib current is (in A)");
+disp(Ibang,"the angle of Ib current is (in degree)");
+//calculating the neutral current
+Inreal=-(Irreal+Iyreal+Ibreal);
+Inimg=-(Irimg+Iyimg+Ibimg);
+Inmag=sqrt(Inreal^2+Inimg^2);
+Inang=atand(Inimg/Inreal);
+disp(Inmag,"the magnitude of neutral current is (in A)");
+disp(Inang,"the degree of neutral current is (in A)");
+//calculating the power in each phase
+Pr=Irmag^2*Z1real;
+Py=Iymag^2*Z2real;
+Pb=Ibmag^2*Z3real;
+P=Pr+Py+Pb;
+disp(P,"the total power absorbed by the load is (in W)");
+//in text book decimal values of variables used in power calculating are rounded off so power varies by 2 watts \ No newline at end of file