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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 3.5
+// Computation for percentage increase in zero-external-field thermoinic-emission current because of the schottky effect//
+// Page no.78
+
+clc;
+clear;
+close;
+
+//Given data ;
+V=500;//plate voltage
+ra=1;//anode radius
+rk=0.01;//cathode radius
+r=10^-4;
+T=2500;
+
+
+
+//Calculation for electric field intensity at the surface of the cathode//
+E=(V/(log(ra/rk)))*(1/r);
+
+//Calculation for percentage increase in zero-external-field thermoinic-emission current because of the schottky effect//
+P1=log(%e^((0.434*0.44*E^(1/2))/T));//P1=log(I/Ith)
+P2=10^0.0796;//P2=I/Ith
+
+//I/Ith=1.20,shows that the schottky theory predicts a 20 percent increase over the zero-field emission current//
+
+
+//Displaying the result in command window
+printf('\n Electric field intensity at the surface of the cathode = %0.3f x 10^6 V/m',E*10^-6);
+printf('\n \n log(I/Ith) = %0.4f ',P1);
+printf('\n \n I/Ith = %0.2f ',P2);
+printf("\n \n \n \n I/Ith=1.20,shows that the Schottky theory predicts a 20 percent increase over the zero-field emission current.");
+
+//Answers are varying due to round off error//