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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3648/CH9/EX9.12/Ex9_12.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3648/CH9/EX9.12/Ex9_12.sce')
-rw-r--r-- | 3648/CH9/EX9.12/Ex9_12.sce | 14 |
1 files changed, 14 insertions, 0 deletions
diff --git a/3648/CH9/EX9.12/Ex9_12.sce b/3648/CH9/EX9.12/Ex9_12.sce new file mode 100644 index 000000000..01082fab5 --- /dev/null +++ b/3648/CH9/EX9.12/Ex9_12.sce @@ -0,0 +1,14 @@ + +//Example 9_12
+clc();
+clear;
+//To find out the sedimentation rate of spherical particles
+b=2*10^-3 //units in cm
+g=9.8 //Units in meters/sec^2
+n=1 //units in m PI
+Pp_Pt=1050 //units in Kg/Meter^3
+vt=(((2*b^2*g)/(9*n))/(2*Pp_Pt))*10^6 //units in cm/sec
+printf("Sedimentation is vt=")
+disp(vt)
+printf("cm/sec")
+//in text book answer is printed wrong as vt=4.36*10^-3 cm/sec but the correct answer is vt=4.14*10^-3 cm/sec
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