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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
treedbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3594/CH2/EX2.4/ex2_4.sce
parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+
+clc
+//given
+m1=150 //lb
+l=3//ft
+//number of oscillation per second is given by n
+printf("\n")
+n=(50/92.5)
+printf ("number of oscillation per second = %.2f\n",n)
+//length of simple pendulum is given by L=g/(2*%pi*n)^2
+L=32.2/(2*%pi*n)^2
+printf ("length of simple pendulum = %.2f ft\n",L)
+// distance of cg from point of suspension is given by a
+a=25/12
+k=(a*(L-a))^.5//radius of gyration
+moi=m1*k^2
+printf("The moment of inertia of rod is %.2f lb ft^2",moi)