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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Clearing console
+clc
+clear
+
+//Intializing Variables
+d = 0.012
+L = 0.1
+k = 200
+c = 900
+p = 2700
+T(1,1) = 80
+T(5,1) = 30
+Td(1,1) = 0
+Td(5,1) = 0
+Q(1:4,1) = ((%pi*d^2)/4)*[4000;0;0;0]
+
+//Calculating elemental conductance and capacitance matrices
+C1 = ((c*p*L*%pi*(d)^2)/(16*6))*[2 1;1 2]
+K1 = ((k*%pi*(d)^2)/(L))*[1 -1;-1 1]
+
+//Calculating globLal capacitance matrices
+C(1,1:5) = [C1(1,1:2) 0 0 0]
+C(2,1:5) = [C1(2,1) C1(2,2)+C1(1,1) C1(1,2) 0 0]
+C(3,1:5) = [0 C1(2,1) C1(2,2)+C1(1,1) C1(1,2) 0]
+C(4,1:5) = [0 0 C1(2,1) C1(2,2)+C1(1,1) C1(1,2)]
+C(5,1:5) = [0 0 0 C1(2,1) C1(2,2)]
+
+//Calculating global conductance matrices
+K(1,1:5) = [K1(1,1:2) 0 0 0]
+K(2,1:5) = [K1(2,1) K1(2,2)+K1(1,1) K1(1,2) 0 0]
+K(3,1:5) = [0 K1(2,1) K1(2,2)+K1(1,1) K1(1,2) 0]
+K(4,1:5) = [0 0 K1(2,1) K1(2,2)+K1(1,1) K1(1,2)]
+K(5,1:5) = [0 0 0 K1(2,1) K1(2,2)]
+
+//Calculating Inverse of Capacitance matrix
+Ci = inv(C(2:4,2:4))
+
+//Caluculating Coefficents Temperature odes
+A = Ci*K(2:4,2:4)
+B = Ci*(Q(2:4,1)-C(2:4,1)*Td(1,1)-C(2:4,5)*Td(5,1)-K(2:4,1)*T(1,1)-K(2:4,5)*T(5,1))
+
+//solving for T2 T3 and T4
+T2(1) =30
+T3(1) =30
+T4(1) =30
+
+for i = 2:301
+ T2(i) = T2(i-1)-(A(1,1:3)*[T2(i-1);T3(i-1);T4(i-1)])+B(1,1)
+ T3(i) = T3(i-1)-(A(2,1:3)*[T2(i-1);T3(i-1);T4(i-1)])+B(2,1)
+ T4(i) = T4(i-1)-(A(3,1:3)*[T2(i-1);T3(i-1);T4(i-1)])+B(3,1)
+end
+
+printf('\nResults\n')
+printf('\nNode-Temperatures \nT2=%fK \nT3=%fK \nT4=%fK',T2(300),T3(300),T4(300))
+