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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+
+// Display mode
+mode(0);
+
+// Display warning for floating point exception
+ieee(1);
+
+clc;
+disp("Introduction to Fluid Mechanics, 3rd Ed. William S. Janna Chapter - 1 Example # 1.4 ")
+
+//Solving part a
+disp("Part a)")
+disp("Part a is theoretical and does not require computation")
+disp("Final result is pi - p0 = 2*sigma/R")
+
+
+//Solving part b
+disp("Part b)")
+//Diameter of droplet in cm
+d = 0.01;//Authors have used 0.01 diameter for calculation while the diameter quoted in question is 0.1
+//Using Appendix table A.5 for properties of water
+//Surface tension sigma in N/m
+sigma = 71.97/1000;
+//Atmospheric pressure for droplet in N/m2 is
+p0 = 101300;
+//Radius of droplet in m
+R = 0.01*(d/2);
+//Calculating pressure inside the droplet in N/m2
+disp("Pressure inside the droplet in N/m2 is")
+pi = p0+(2*sigma)/R
+//Answer varies slightly because of round-off error