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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3556/CH11/EX11.15/Ex11_15.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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diff --git a/3556/CH11/EX11.15/Ex11_15.sce b/3556/CH11/EX11.15/Ex11_15.sce new file mode 100644 index 000000000..8bd079bf8 --- /dev/null +++ b/3556/CH11/EX11.15/Ex11_15.sce @@ -0,0 +1,33 @@ +clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 2 : AC Circuits
+// Chapter 11 : AC power Analysis
+// Example 11 - 15
+
+clear; clc; close;
+//
+// Given data
+pf_old = 0.8000;
+pf_new = 0.9500;
+f = 60.0000;
+Vrms_mag = 120.0000;
+Vrms_angle = 0.0000;
+P_load = 4.0000;
+Vrms = complex(Vrms_mag*cosd(Vrms_angle),Vrms_mag*sind(Vrms_angle))
+// Calculations S1 dan Q1
+S1 = (P_load*1000)/pf_old;
+Q1 = S1 * sind(acosd(pf_old));
+// Calculations S2 dan Q2
+S2 = (P_load*1000)/pf_new;
+Q2 = S2 * sind(acosd(pf_new));
+// Calculations Reactive Power of Capacitors and Capacitance of Capacitors
+Qc = Q1 - Q2;
+C = Qc/(2*%pi*f*(Vrms_mag)^2);
+//
+disp("Example 11-15 Solution : ");
+printf(" \n a. Qc = Reactive Power of Capacitors = %.3f VAR",Qc)
+printf(" \n a. C = Capacitance of Capacitors = %.7f MikroFarad",C*1000000)
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