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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3554/CH13/EX13.4/Ex13_4.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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Diffstat (limited to '3554/CH13/EX13.4/Ex13_4.sce')
| -rw-r--r-- | 3554/CH13/EX13.4/Ex13_4.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/3554/CH13/EX13.4/Ex13_4.sce b/3554/CH13/EX13.4/Ex13_4.sce new file mode 100644 index 000000000..6c1a6e03b --- /dev/null +++ b/3554/CH13/EX13.4/Ex13_4.sce @@ -0,0 +1,22 @@ +// Exa 13.4
+
+clc;
+clear all;
+
+// Given data
+
+R= 4;// Resistance of thermistor in k Ohms
+R1=0.003;// Meter resistance in k Ohms
+Rc=0.017; // in k Ohms
+Vt=15;// in Volts
+
+// Solution
+
+// From fig. 13.2(b)- graph of Temp vs Resistance we find that,thermistor resistance at 25 degree Celsius is 4 K ohms and at 65.5556 degree Celsius it is 950 ohms.
+R_25= 4;// in k Ohms
+R_65=0.95; // in k Ohms
+
+I1=Vt/(R_25+R1+Rc); // current at 25 degree Celsius(A)
+I2=Vt/(R_65+R1+Rc); // current at 65.556 degree Celsius(A)
+
+printf(' The current meter reading at 25 degree Celsius = %.2f mA and at 150 degree fahrenheit = %.1f mA \n', I1,I2);
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