initial commit / add all books

16 files changed, 208 insertions, 0 deletions

diff --git a/3542/CH9/EX9.1/9_1.jpg b/3542/CH9/EX9.1/9_1.jpg
new file mode 100644
index 000000000..f26361ce6
--- /dev/null
+++ b/3542/CH9/EX9.1/9_1.jpg
diff --git a/3542/CH9/EX9.1/Ex9_1.sce b/3542/CH9/EX9.1/Ex9_1.sce
new file mode 100644
index 000000000..dd160e1ea
--- /dev/null
+++ b/3542/CH9/EX9.1/Ex9_1.sce
@@ -0,0 +1,48 @@
+// Example no 9.1

+// To find the intermodulation frequencies generated 

+// Page no. 451

+

+clc;

+clear all;

+

+// Given data

+f1=1930;                                         // First carrier frequency

+f2=1932;                                         // second carrier frequency

+F1=1920;                                         // Lower frequency of the band

+F2=1940;                                         // Upper frequency of the band

+

+for n=0:3

+    x1=(2*n+1)*f1-2*n*f2

+    if x1 < = F2 then

+        printf('\n IF frequency %0.0f MHz lies inside the band',x1);

+    else

+        printf('\n IF frequency %0.0f MHz lies outside the band',x1);

+    end

+end

+

+for n=0:3

+    x2=(2*n+2)*f1-(2*n+1)*f2

+    if x2 < = F2 then

+        printf('\n IF frequency %0.0f MHz lies inside the band',x2);

+    else

+        printf('\n IF frequency %0.0f MHz lies outside the band',x2);

+    end

+end

+

+for n=0:3

+    x3=(2*n+1)*f2-2*n*f1

+    if x3 < = F2 then

+        printf('\n IF frequency %0.0f MHz lies inside the band',x3);

+    else

+        printf('\n IF frequency %0.0f MHz lies outside the band',x3);

+    end

+end

+

+for n=0:3

+    x4=(2*n+2)*f2-(2*n+1)*f1

+    if x4 < = F2 then

+        printf('\n IF frequency %0.0f MHz lies inside the band',x4);

+    else

+        printf('\n IF frequency %0.0f MHz lies outside the band',x4);

+    end

+end

diff --git a/3542/CH9/EX9.2/9_2.jpg b/3542/CH9/EX9.2/9_2.jpg
new file mode 100644
index 000000000..753b2595b
--- /dev/null
+++ b/3542/CH9/EX9.2/9_2.jpg
diff --git a/3542/CH9/EX9.2/Ex9_2.sce b/3542/CH9/EX9.2/Ex9_2.sce
new file mode 100644
index 000000000..39c7ad686
--- /dev/null
+++ b/3542/CH9/EX9.2/Ex9_2.sce
@@ -0,0 +1,17 @@
+// Example no 9.2

+// To find number of channels available

+// Page no. 452

+

+clc;

+clear all;

+

+// Given data

+Bt=12.5*10^6;                                            // Total spectrum allocation in Hz

+Bguard=10*10^3;                                          // Guard band allocated in Hz

+Bc=30*10^3;                                              // Channel bandwidth in Hz

+

+// The number of channels available

+N=(Bt-2*Bguard)/Bc;                                      // The number of channels available

+

+// Displaying the result in command window

+printf('\n The number of channels available in FDMA system = %0.0f',N);

diff --git a/3542/CH9/EX9.3/9_3.jpg b/3542/CH9/EX9.3/9_3.jpg
new file mode 100644
index 000000000..7237db172
--- /dev/null
+++ b/3542/CH9/EX9.3/9_3.jpg
diff --git a/3542/CH9/EX9.3/Ex9_3.sce b/3542/CH9/EX9.3/Ex9_3.sce
new file mode 100644
index 000000000..10da69a7f
--- /dev/null
+++ b/3542/CH9/EX9.3/Ex9_3.sce
@@ -0,0 +1,18 @@
+// Example no 9.3

+// To find number of simultaneous users accommodated in GSm

+// Page no. 455

+

+clc;

+clear all;

+

+// Given data

+m=8;                                                // Maximum speech channels supported by single radio channel

+Bc=200*10^3;                                        // Radio channel bandwidth in Hz

+Bt=25*10^6;                                         // Total spectrum allocated for forward link

+Bguard=0;                                           // Guard band allocated in Hz

+

+// The number of simultaneous users accommodated in GSm

+N=(m*(Bt-2*Bguard))/Bc;                             // The number of simultaneous users

+

+// Displaying the result in command window

+printf('\n The number of simultaneous users accommodated in GSM system = %0.0f',N);

diff --git a/3542/CH9/EX9.4/9_4.jpg b/3542/CH9/EX9.4/9_4.jpg
new file mode 100644
index 000000000..b7a6894a7
--- /dev/null
+++ b/3542/CH9/EX9.4/9_4.jpg
diff --git a/3542/CH9/EX9.4/Ex9_4.sce b/3542/CH9/EX9.4/Ex9_4.sce
new file mode 100644
index 000000000..afe152911
--- /dev/null
+++ b/3542/CH9/EX9.4/Ex9_4.sce
@@ -0,0 +1,29 @@
+// Example no 9.4

+// To find a)the time duration of a bit b)the time duration of a slot c)the time duration of a frame d)how long must a user occupying single time slot wait between two successive transmission

+// Page no. 456

+

+clc;

+clear all;

+

+// Given data

+N=8;                                                        // Number of time slots in each frame

+Nb=156.25;                                                  // Number of in each time slot

+DR=270.833*10^3;                                            // Data rate of transmission in channel

+

+// a)To find the time duration of a bit 

+Tb=1/DR;                                                   // The time duration of a bit in sec

+

+// b)To find the time duration of a slot

+Tslot=Nb*Tb;                                              // The time duration of a slot

+

+// c)To find the time duration of a frame

+Tf=N*Tslot;                                               // The time duration of a frame

+

+//d) The waiting time between two successive transmission

+Tw=Tf;                                                   // The arrival time of new frame for its next transmission

+

+// Displaying the result in command window

+printf('\n The time duration of a bit = %0.3f microseconds',Tb*10^6);

+printf('\n The time duration of a slot = %0.3f ms',Tslot*10^3);

+printf('\n The time duration of a frame = %0.3f ms',Tf*10^3);

+printf('\n The arrival time of new frame for its next transmission = %0.3f ms',Tw*10^3);

diff --git a/3542/CH9/EX9.5/9_5.jpg b/3542/CH9/EX9.5/9_5.jpg
new file mode 100644
index 000000000..7fcdca6fc
--- /dev/null
+++ b/3542/CH9/EX9.5/9_5.jpg
diff --git a/3542/CH9/EX9.5/Ex9_5.sce b/3542/CH9/EX9.5/Ex9_5.sce
new file mode 100644
index 000000000..b7439460a
--- /dev/null
+++ b/3542/CH9/EX9.5/Ex9_5.sce
@@ -0,0 +1,24 @@
+// Example no 9.5

+// To find the frame efficiency

+// Page no. 456

+

+clc;

+clear all;

+

+// Given data

+Btrail=6;                                               // Number of trailing bits per slot

+Bg=8.25;                                                // Number of guard bits per slot

+Btrain=26;                                              // Number of training bits per slot

+Nb=2;                                                   // Number of burst

+Bburst=58;                                              // Number of bits in each burst

+Nslot=8;                                                // Number of slots in each frame

+

+N=Btrail+Bg+Btrain+2*Bburst;                            // Total number of bits in each slot

+Nf=Nslot*N;                                             // Total number of bits in a frame

+bOH=Nslot*Btrail+Nslot*Bg+Nslot*Btrain;                 // Number of overhead bits per frame

+

+// To find the frame efficiency

+nf=(1-(bOH/Nf))*100;                                   // Frame efficiency

+

+// Displaying the result in command window

+printf('\n The frame efficiency = %0.2f percentage',nf);

diff --git a/3542/CH9/EX9.6/9_6.jpg b/3542/CH9/EX9.6/9_6.jpg
new file mode 100644
index 000000000..74470d005
--- /dev/null
+++ b/3542/CH9/EX9.6/9_6.jpg
diff --git a/3542/CH9/EX9.6/Ex9_6.sce b/3542/CH9/EX9.6/Ex9_6.sce
new file mode 100644
index 000000000..856823f85
--- /dev/null
+++ b/3542/CH9/EX9.6/Ex9_6.sce
@@ -0,0 +1,20 @@
+// Example no 9.6

+// To determine the maximum throughput using ALOHA and slotted ALOHA

+// Page no. 466

+

+clc;

+clear all;

+

+//The maximum throughput using ALOHA

+Rmax=1/2;                                            //Maximum rate of arrival calculated by equating ALOHA throughput formula derivative to zero

+T=Rmax*exp(-1);                                      //The maximum throughput using ALOHA

+

+// Displaying the result in command window

+printf('\n The maximum throughput using ALOHA = %0.4f',T);

+

+//The maximum throughput using slotted ALOHA

+Rmax=1;                                              //Maximum rate of arrival calculated by equating slotted ALOHA throughput formula derivative to zero

+T=Rmax*exp(-1);                                      //The maximum throughput using slotted ALOHA

+

+// Displaying the result in command window

+printf('\n The maximum throughput using slotted ALOHA = %0.4f',T);

diff --git a/3542/CH9/EX9.7/9_7.jpg b/3542/CH9/EX9.7/9_7.jpg
new file mode 100644
index 000000000..9c2efb4d2
--- /dev/null
+++ b/3542/CH9/EX9.7/9_7.jpg
diff --git a/3542/CH9/EX9.7/Ex9_7.sce b/3542/CH9/EX9.7/Ex9_7.sce
new file mode 100644
index 000000000..d1f70a14f
--- /dev/null
+++ b/3542/CH9/EX9.7/Ex9_7.sce
@@ -0,0 +1,29 @@
+// Example no 9.7

+// To evaluate 4 different radio standards and to choose the one with maximum capacity

+// Page no. 472

+

+clc;

+clear all;

+

+// Given data

+ABc=30*10^3;                                              // Channel bandwidth of system A

+ACImin=18;                                                // The tolerable value of carrier to interference ratio for system A

+BBc=25*10^3;                                              // Channel bandwidth of system B

+BCImin=14;                                                // The tolerable value of carrier to interference ratio for system B

+CBc=12.5*10^3;                                           // Channel bandwidth of system C

+CCImin=12;                                                // The tolerable value of carrier to interference ratio for system C // Value of CCImin is given wrong in book

+DBc=6.25*10^3;                                           // Channel bandwidth of system D

+DCImin=9;                                                // The tolerable value of carrier to interference ratio for system D

+Bc=6.25*10^3;                                            // Bandwidth of particular system

+

+ACIeq=ACImin+20*log10(Bc/ABc);                           // Minimum C/I for system A when compared to the (C/I)min for particular system

+BCIeq=BCImin+20*log10(Bc/BBc);                           // Minimum C/I for system B when compared to the (C/I)min for particular system

+CCIeq=CCImin+20*log10(Bc/CBc);                           // Minimum C/I for system C when compared to the (C/I)min for particular system

+DCIeq=DCImin+20*log10(Bc/DBc);                           // Minimum C/I for system D when compared to the (C/I)min for particular system

+

+// Displaying the result in command window

+printf('\n Minimum C/I for system A when compared to the (C/I)min for particular system = %0.3f dB',ACIeq);

+printf('\n Minimum C/I for system B when compared to the (C/I)min for particular system = %0.2f dB',BCIeq);

+printf('\n Minimum C/I for system C when compared to the (C/I)min for particular system = %0.0f dB',CCIeq); 

+printf('\n Minimum C/I for system D when compared to the (C/I)min for particular system = %0.0f dB',DCIeq);

+printf('\n \n Based on comparison, the smallest value of C/I should be selected for maximum capacity. So, System B offers the best capacity.')

diff --git a/3542/CH9/EX9.9/9_9.jpg b/3542/CH9/EX9.9/9_9.jpg
new file mode 100644
index 000000000..7e9c10914
--- /dev/null
+++ b/3542/CH9/EX9.9/9_9.jpg
diff --git a/3542/CH9/EX9.9/Ex9_9.sce b/3542/CH9/EX9.9/Ex9_9.sce
new file mode 100644
index 000000000..41c515a1e
--- /dev/null
+++ b/3542/CH9/EX9.9/Ex9_9.sce
@@ -0,0 +1,23 @@
+// Example no 9.9

+// To determine the maximum number of users using a)omnidirectional base station antenna and no voice activity b)three-sectors at the base station and voice activity detection

+// Page no. 472

+

+clc;

+clear all;

+

+// Given data

+W=1.25*10^6;                                                                  // Total RF bandwidth in Hz

+R=9600;                                                                       // Baseband information bit rate in bps

+EbNo=10;                                                                      // Minimum acceptable SNR in dB

+

+// a)Maximum number of users using omnidirectional base station antenna and no voice activity

+N1=1+(W/R)/EbNo;                                                              // Maximum number of users using omnidirectional

+

+// b)Maximum number of users using three-sectors at the base station antenna and voice activity with alpha=3/8

+alpha=3/8;                                                                    // Voice activity factor

+Ns=1+(1/alpha)*((W/R)/EbNo);                                                  // Maximum number of users

+N2=3*Ns;                                                                      // Maximum number of users using three-sectors

+

+// Displaying the result in command window

+printf('\n Maximum number of users using omnidirectional base station antenna and no voice activity = %0.0f',N1);

+printf('\n Maximum number of users using three-sectors at the base station antenna and voice activity (with alpha=3/8) = %0.0f',N2);