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+//Example 2// Ch 5

+clc;

+clear;

+close;

+// given data

+d = 0.001;//in meters

+p = 101.3; //gas pressure in kPa

+C = -2400.4;//constant value

+A = 0.027;//constant value

+As = 10^8;//avalanche size

+//secondary ionization coefficient is much smaller than unity therefore ionization coefficient (alpha) is equal to electron attachment coefficient 

+E = (2400.4*p)/0.027; //alpha is equal to e- attachment coeff occurs at this eq

+Vs1 = E*d;//breakdown voltage in V

+printf("electric field %e V/m \n",E)

+printf("breakdown voltage %f V \n",Vs1)

+Vs2 = (log(As)-C*p*d)/A; //in V

+printf("breakdown voltage corresponding to an avalanche size %f V \n",Vs2)

+//as the avalanche self-space charge is neglected the breakdown voltage will be same irrespective of the polarity of the stressed plate acc. to eq (5.4) N2>=N1;

+Vspos = 9.4;//in kV when N2>=N1 in which no of e- in second avalanche is greater than equal to no of e- in first avalanche

+printf("positive voltage breakdown %f kV \n",Vspos)

+Vsneg = 9.2;//in kV when Neph >= 1 where Neph is no of e-photoemitted from the cathode

+printf("negative voltage breakdown %f kV \n",Vsneg)