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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 6 // Ch 2
+clc;
+clear;
+close;
+// given data
+V=400*10^3; // applied voltage in kV
+r_eq=0.08874; // equivalent radius in meters
+H=12; // bundle height in meters
+d=9; // pole to pole spacing in meters
+Epsilon_o=8.85*10^-12;
+x=sqrt((2*H)^2 + d^2);
+Q = (V*2*%pi*Epsilon_o) / [(log(2*H/r_eq)) - log(x/d)];
+q = Q/2;
+printf("charge per bundle is %e C/m \n",Q)
+printf("charge per subconductor is %e C/m \n",q)
+r = 0.0175; //subconductor radius in meters
+R = 0.45; //subconductor-to-subconductor spacing in meters
+q = 2.44*1e-6; //charge per subconductor in C/m
+d = 9; //in meters
+Epsilon_o = 8.85*10^-12; //in F/m
+x=[(1/r) + (1/R)];
+y=[(1/r) - (1/R)];
+
+Max = (q/(2*%pi*Epsilon_o))*(x); //maximum surface field in V/m
+printf("maximum surface field is %e V/m \n ", Max)
+
+Min = (q/(2*%pi*Epsilon_o))*[y]; //minimum surface field in V/m
+printf("minimum surface field is %f V/m \n", Min)
+
+Avg = (q/(2*%pi*Epsilon_o))*[1/r]; //average surface field in V/m
+printf("average surface field is %f V/m \n", Avg)
+
+E_01 = [(q/(2*%pi*Epsilon_o))*[1/r + 1/R]] - [(q/(2*%pi*Epsilon_o))*[1/(d+r)+1/(d+R+r)]];//field at outer point of subconductor in V/m
+disp(E_01, "field at outer point of subconductor 1(V/m) =")
+E_02 = [(q/(2*%pi*Epsilon_o))*[1/r + 1/R]] - [(q/(2*%pi*Epsilon_o))*[1/(d-R-r)+1/(d-r)]];
+disp(E_02, "field at outer point of subconductor 2(V/m) =")
+E_l1 = [(q/(2*%pi*Epsilon_o))*[1/r - 1/R] - (q/(2*%pi*Epsilon_o))*[1/(d-r)+1/(d+R-r)]];
+disp(E_l1, "field at inner point of subconductor 1(V/m) =")
+E_l2 = [(q/(2*%pi*Epsilon_o))*[1/r - 1/R] - (q/(2*%pi*Epsilon_o))*[1/(d-R-r)+1/(d+R)]];
+disp(E_l2, "field at inner point of subconductor 2(V/m) =")
+Avg = (E_01 + E_02)/2 // average maximum gradient in V/m
+disp(Avg, "average maximum gradient is")
+
+//answers in the book is wrong for subconductor 2, El1 and El2