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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 6.3
+format('v',5);
+clc;
+clear;
+close;
+// Given data
+f=2;// in kHz
+f=f*10^3;// in Hz
+// Let
+R= 10;// in kohm (As R should be greater than 1 kohm)
+R=R*10^3;// in ohm
+// Formula f= 1/(2*%pi*R*C)
+C= 1/(2*%pi*f*R);// in F
+C= C*10^9;// in nF
+// For Bita to be 1/3, Choose
+R4= R;// in ohm
+R3= 2*R4;// in ohm
+disp(C,"Value of C in nF is : ")
+disp(R3*10^-3,"Value of R3 in kohm is : ")
+disp(R4*10^-3,"Value of R4 in kohm is : ")
+