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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 5.20
+format('v',5);
+clc;
+clear;
+close;
+// Given data
+A= 100;
+Vs=1;// in volt
+Bita=1;// as in the voltage follower, the output voltage is same as input
+Af= A/(1+Bita*A);
+CLG= 1+A*Bita;// closed loop gain
+disp(CLG,"Closed loop gain is : ")
+CLG_dB= 20*log10(CLG);
+disp(CLG_dB,"Closed loop gain in dB is : ")
+Vo= Af*Vs;// in V
+disp(Vo,"Value of Vo in volt is : ")
+Vi= Vs-Vo;// in V
+disp(round(Vi*10^3),"Value of Vi in mV is : ")
+// If A decrease 10%,i.e.
+A=90;
+Af_desh= A/(1+Bita*A);
+Per_gain_reduction= (Af_desh-Af)/Af*100;// in %
+disp(Per_gain_reduction,"Percentage of gain reduction in %")