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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 3.23
+format('v',5);
+clc;
+clear;
+close;
+// Given data
+VBE= 0.7;// in V
+VCC= 9;// in V
+VCE= -9;// in V
+V_B= -1.5;// in V
+R_C= 10;// in kΩ
+R_C=R_C*10^3;// in Ω
+R_B= 10;// in kΩ
+R_B=R_B*10^3;// in Ω
+I_B= abs(V_B)/R_B;// in A
+V_E= V_B-VBE;// in V
+disp(V_E,"The value of V_E in volt is : ")
+I_E= (V_E-VCE)/R_B;// in A
+Beta= I_E/I_B-1;
+alpha= Beta/(1+Beta);
+disp(alpha,"The value of alpha in volt is : ")
+disp(Beta,"The value of Beta in volt is : ")
+V_C= VCC-I_E*alpha*R_C;// in V
+disp(V_C,"The value of V_C in volt is : ")
+// When Beta = infinite then
+alpha= 1 ;// As infinite/(1+infinite) = 1
+I_B= 0;
+V_B=0;
+V_C= VCC-I_E*R_C;// in volt
+disp("When Beta = infinite then :-")
+disp(V_B,"The value of V_B in volt is : ")
+disp(V_E,"The value of V_E in volt is : ")
+disp(V_C,"The value of V_C in volt is : ")