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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 2.14
+format('v',7);
+clc;
+clear;
+close;
+// Given data
+V_GS1= 1.5;// in V
+Vt= 1;// in V
+r_DS1= 1;// in kΩ
+r_DS1= r_DS1*10^3;// in Ω
+r_DS2= 200;// in kΩ
+// r_DS1= 1/(KnWbyL*(V_GS1-Vt)) (i)
+// r_DS2= 1/(KnWbyL*(V_GS2-Vt)) (i)
+// dividing equation (i) by (ii)
+V_GS2= (r_DS1/r_DS2)*(V_GS1-Vt)+Vt;// in V
+disp(V_GS2,"To Optain rDS= 200, The value of V_GS should be (in volt)")
+// For V_GS= 1.5 ;// V
+// W2= 2*W1;
+// r_DS1/r_DS2= 2
+r_DS2= r_DS1/2;// in Ω
+disp(r_DS2,"For V_GS= 1.5 V , the value of r_DS2 in Ω is : ")
+// For V_GS= 3.5 V
+r_DS2= 200/2;// in Ω
+disp(r_DS2,"For V_GS= 3.5 V , the value of r_DS2 in Ω is : ")