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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// To determine percentage of specimens
+//page no 22
+clear
+clc;
+m=10;// cm mean
+sd=0.03;// standard deviation
+x=10.075;
+z=0.9938 //The values of Z from normal tables
+z=z*100;
+t=100-z;
+mprintf("Therefore 100-99.38 = %.2f percent of items are falling greater than 10.075 cms.",t);
+//(b)
+z=1.04;
+x=(z*sd)-m;
+mprintf("\nBelow %.2f value of diameter will 15 percentage piston rings fall",x);