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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//chapter9
+//example9.5
+//page147
+
+E1=24 // V
+E2=4 // V
+Vo=0.7 // V
+R=2 // kilo ohm
+
+// diode D1 is forward biased and diode D2 is reverse biased so
+I=(E1-E2-Vo)/R
+
+printf("current in the circuit = %.3f mA \n",I)