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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//chapter16
+//example16.11
+//page352
+
+Av=1000
+mv=0.01
+f1=1.5 // kHz
+f2=501.5 // kHz
+
+f_1f=f1/(1+Av*mv)
+f_2f=f2*(1+mv*Av)
+
+printf("new lower cutoff frequency with negative feedback = %.3f kHz or %.3f Hz \n",f_1f,f_1f*1000)
+printf("new upper cutoff frequency with negative feedback = %.3f kHz or %.3f MHz \n",f_2f,f_2f/1000)
+
+// the accurate answers are 136.364 Hz and 5.516 MHz but in book they are given as 136.4 Hz and 5.52 MHz respectively