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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3507/CH14/EX14.7/Ex14_7.sce | |
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initial commit / add all books
Diffstat (limited to '3507/CH14/EX14.7/Ex14_7.sce')
| -rw-r--r-- | 3507/CH14/EX14.7/Ex14_7.sce | 19 |
1 files changed, 19 insertions, 0 deletions
diff --git a/3507/CH14/EX14.7/Ex14_7.sce b/3507/CH14/EX14.7/Ex14_7.sce new file mode 100644 index 000000000..cbc051eab --- /dev/null +++ b/3507/CH14/EX14.7/Ex14_7.sce @@ -0,0 +1,19 @@ +//chapter 14
+//example 14.7
+//page 302
+
+Ao_db=70 // db
+Av_db=67 // db
+Rout=1.5 // kilo ohm
+
+// since 20*log(Ao)-20*log(Av)=Ao_db-Av_db we get
+// 20*log(Ao/Av) = Ao_db-Av_db so
+// Ao/Av = 10^((Ao_db-Av_db)/20)
+// and also Ao/Av=1+Rout/Rl since Av/Ao=Rl/(Rl+Rout)
+
+// so making Rl as subject we get
+Rl=Rout/(10^((Ao_db-Av_db)/20)-1)
+
+printf("minimum value of load resistance = %.3f kilo ohm \n",Rl)
+
+// the accurate answer is 3.636 kilo ohm
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