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authorpriyanka2015-06-24 15:03:17 +0530
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+//chapter 14
+//example 14.2
+//page 301
+
+Ap1=40 // db
+Ap2=43 // db
+
+// since Ap = 10*log10(power_gain), we get
+power_gain1=10^(Ap1/10)
+power_gain2=10^(Ap2/10)
+
+printf("power gain of 40 db = %.3f \n",power_gain1)
+printf("power gain of 43 db = %.3f \n",power_gain2)
+
+// the accurate answer for power gain of 43 db is 19952 but in book it is given as 20000 db