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authorpriyanka2015-06-24 15:03:17 +0530
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+//chapter12
+//example12.6
+//page242
+
+Vcc=10 // V
+R_B=1d3 // kilo ohm
+R_E=1 // kilo ohm
+Vbe=0 // since it is negligible
+gain_beta=100
+
+// by Kirchoff voltage law to base side we get Vcc=I_B*R_B+Vbe+I_E*R_E
+// but I_E=I_B+I_C and I_C=gain_beta*I_B
+// so we get Vcc=I_B*R_B+Vbe+R_E*I_B*(1+gain_beta)
+// making I_B as subject we get
+
+I_B=(Vcc-Vbe)/(R_B+R_E*(1+gain_beta)) // in ampere
+I_C=gain_beta*I_B // in ampere
+I_E=I_C+I_B // in ampere
+
+printf("base current = %.4f mA \n",I_B)
+printf("collector current = %.4f mA \n",I_C)
+printf("emitter current = %.4f mA \n",I_E)