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authorpriyanka2015-06-24 15:03:17 +0530
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+clc
+//Chapter2
+//Ex_2.5
+//Given
+d=8.96*10^3 //in Kg/m3
+NA=6.02*10^23 //mol^-1
+Mat=63.56*10^-3 //Kg/mol
+k=1.38*10^-23 //J/K
+T=300 //kelvin
+e=1.6*10^-19 //in couloumbs
+m_e= 9.1*10^-31 //in Kg
+u=1.25*10^6//m/s
+f=4*10^12 //frequency in s^-1
+Ns=d*NA/Mat// atomic concentration in m^-3
+M=Mat/NA
+w=2*%pi*f //angular frequency of the vibration
+//by virtue of Equipartition of energy theorem
+a=sqrt((2*k*T)/(M*w^2))
+S=%pi*a^2 //cross sectional area
+t=1/(S*u*Ns) //mean free time
+u_d=e*t/m_e //drift velocity
+u_d=u_d*10^4 //change in units
+Ns=Ns/10^6 //in cm^-3
+sigma=e*Ns*u_d //conductivity
+disp(u_d,"drift velocity of electrons in m2/V/s is")
+disp(sigma," conductivity of copper in ohm^-1/cm is")
+//slight change in the answer is due to the computation method, otherwise answer is matching with textbook