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+//Chapter 1,Example 1.2 Page 52
+clc
+clear
+// Refering the table in example 1.2
+// slope between any two points (log(I/I0)/x)
+// taking the gap between 2 and 2.5 mm
+I1= 1.5*10^-12
+I2= 5.6*10^-12
+I0 = 6*10^-14
+gi1 = log(I1/I0) // gradual increase when gap is 2
+gi2 = log(I2/I0) // gradual increase when gap is 2.5 //claculation in text is wrong
+slope = (gi1-gi2)/0.05
+printf(" Slope = %f \n", -slope) 
+//evaluvating ghama
+e1 = exp(-slope*0.5)
+e2 = exp(-slope*0.5) // -1 is ignored due to the large magnitude
+ghama = (7*10^7-6*e1)/(e2*7*10^7)
+printf(" Ghama for set 1= %e /cm \n ", ghama)
+//Gap between the slope for set 2
+alpha = log(12/8)/0.05
+printf(" Alpha = %e collosions/cm \n", alpha)
+e1 = exp(alpha*0.5)
+e2 = exp(alpha*0.5) // -1 is ignored due to the large magnitude
+ghama = (2*10^5-e1)/(e2*2*10^5)
+printf(" Ghama for set 2= %e colissions/cm \n", ghama)
+
+//Answers may vary due to round of error